- 专项训练之循环结构
11
- 2023-8-3 9:54:18 @
#include<bits/stdc++.h>
using namespace std;
int main()
{
double n=0,a=0,he=0;
double b=0;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a;
he=he+a;
}
b=1.0*he/n;
cout<<he<<" ";
printf("%.5f",b);
return 0;
}11
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