- 时间规划-GESP202306一级题一
dn
- 2024-3-23 20:18:55 @
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,d;
cin>>a>>b>>c>>d;
int e=(c-a)*60;
e+=d-b;
cout<<e;
return 0;
}
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Information
- ID
- 725
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 6
- Tags
- # Submissions
- 91
- Accepted
- 31
- Uploaded By