#838. for嵌套if,break,continue

for嵌套if,break,continue

以下程序段的输出结果是({{ input(1) }} )

int x,y;
for(y=1,x=1;y<=50;y++)
{
	if(x>=0) break;
        if(x%2==1) 
	{
		x+=5;
		continue;
	}
	x-=3;
}
printf("%d\n",y);